Extra övningsblad i formelhantering Formel Uppgift Svar

2012-08-23

Extra övningsblad i formelhantering

Formel Uppgift Svar

2

1 R

R

R_ers = + R1 skall bli fritt _______________

I R E

U = − _i⋅ E skall bli fritt _______________

at v

v= 0 + v0 skall bli fritt _______________

at v

v= 0 + a skall bli fritt _______________

2 2

2 b c

a + = c skall bli fritt _______________

2 2

2 b c

a + = a skall bli fritt _______________

t v s

Δ

= Δ Δs skall bli fritt _______________

t v s

Δ

= Δ Δt skall bli fritt _______________

gh

p =ρ ρ skall bli fritt _______________

g h p =

ρ p skall bli fritt _______________

g h p = ρ

1 p skall bli fritt _______________

g h p

ρ = p skall bli fritt _______________

gh p ρ

1

1 = p skall bli fritt _______________

kT E_k

2

= 3 T skall bli fritt _______________

pV =NkT T skall bli fritt _______________

2 2 1

r Q kQ

F = k skall bli fritt _______________

b b i

i n

n ⋅^sinα = ^sinα nb skall bli fritt _______________

T v ²πr

= T skall bli fritt _______________

T v ²πr

= r skall bli fritt _______________

r f

a=4π^{2 2} r skall bli fritt _______________

r f

a=4π^{2 2} f skall bli fritt _______________

2 2 1 1 2 2 1

1u m u mv m v

m + = + ^m2v2 skall bli fritt _______________

2 2 1 1 2 2 1

1u m u mv m v

m + = + ^v2 skall bli fritt _______________

2 2 1 1 2 2 1

1u m u mv m v

m + = + ^m2 skall bli fritt _______________

2 2 1

r Q kQ

F = r skall bli fritt _______________

2012-08-23

Formel Uppgift Facit

2

1 R

R

R_ers = + R1 skall bli fritt R₁ = R_ers −R₂

I R E

U = − _i⋅ E skall bli fritt E =U+R_i⋅I

at v

v= 0 + v0 skall bli fritt v0 =v−at

at v

v= 0 + a skall bli fritt

t v a v− ⁰

=

2 2

2 b c

a + = c skall bli fritt c= a² +b²

2 2

2 b c

a + = a skall bli fritt a= c² −b²

t v s

Δ

= Δ Δs skall bli fritt Δ^s=^v⋅Δ^t

t v s

Δ

= Δ Δt skall bli fritt

v t Δs

= Δ gh

p =ρ ρ skall bli fritt

gh

= p ρ g h

p =

ρ p skall bli fritt p=hρg

g h p = ρ

1 p skall bli fritt p=hρg

g h p

ρ = p skall bli fritt p=hρg

gh p ρ

1

1 = p skall bli fritt p= ρgh

kT E_k

2

= 3 T skall bli fritt

k T E^k

3

= 2

pV =NkT T skall bli fritt

Nk T = pV

2 2 1

r Q kQ

F = k skall bli fritt

2 1

2

Q Q k = Fr

b b i

i n

n ⋅^sinα = ^sinα nb skall bli fritt

b i i b

n n

α α sin

= sin

T v ²πr

= T skall bli fritt

v T ²πr

=

T v ²πr

= r skall bli fritt

2π r = vT r

f

a=4π^{2 2} r skall bli fritt _{2 2}

4 f

r a

= π r

f

a=4π^{2 2} f skall bli fritt

r f a₂

4π

=

2 2 1 1 2 2 1

1u m u mv m v

m + = + ^m2v2 skall bli fritt m₂v₂ =m₁u₁+m₂u₂ −m₁v₁

2012-08-23

2 2 1 1 2 2 1

1u m u mv m v

m + = + ^v2 skall bli fritt

2

1 1 2 2 1 1

2 m

v m u m u

v m + −

=

2 2 1 1 2 2 1

1u m u mv m v

m + = + ^m2 skall bli fritt

2 2

1 1 1 1

2 u v

u m v m m

−

= −

2 2 1

r Q kQ

F = r skall bli fritt

F Q kQ r = ^{1 2}