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Examensarbete i matematik, 15 hp Handledare: Veronica Crispin Quinonez Examinator: Jörgen Östensson

Juni 2016

Department of Mathematics Uppsala University

Powers and Products of Monomial Ideals

Melker Epstein

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Melker Epstein June 16, 2016

1

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Abstract

This thesis is about powers and products of monomial ideals in polynomial rings. We find necessary and sufficient conditions on pow- ers and products of monomial ideals on the polynomial ring K[x, y] for their graphs to take certain staircase-like shapes. In the case of powers, these shapes are repeated for each higher power, so that knowledge of the conditions simplifies the calculation of the powers. We also explore connections to areas of commutative algebra where powers of ideals are important, notably the Hilbert and Hilbert-Samuel functions in dimension theory.

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Contents

1 Introduction and preliminary concepts 3

1.1 Rings and ideals . . . 3 1.2 Modules . . . 6 2 Monomial ideals and conditions on their powers and prod-

ucts 8

2.1 Polynomial rings and monomial ideals . . . 8 2.2 Powers of monomial ideals . . . 15 2.3 Products of monomial ideals . . . 27 3 Connections with other areas: the Hilbert and Hilbert-Samuel

functions 31

3.1 Graded rings and the Hilbert function . . . 31 3.2 Local rings, localization, and Noetherian rings . . . 32 3.3 The Hilbert-Samuel function . . . 35

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1 Introduction and preliminary concepts

The thesis consists of three sections. This first section contains definitions and explanations of concepts and some basic results required to understand the second section, and some of the concepts required for the third section. In the second section, we find and prove conditions on monomial ideals for their powers and products to have a certain form. In the third and last section, we define and explain the Hilbert and Hilbert-Samuel function, before showing how they may be calculated in a simple way on the polynomial ring K[x, y]

by applying the conditions found in section 2.

The first section consists of three subsections. The first subsection is con- cerned with basic properties and operations on rings and ideals. The second subsection introduces the concept of a module, which will be fundamental for the later discussion of the Hilbert and Hilbert-Samuel functions. In the third subsection, polynomial rings and monomial ideals are introduced, as well as their graphs and the notion of a staircase ideal. Most of the definitions in this section will follow David Eisenbud, Commutative algebra. [1]

1.1 Rings and ideals

A ring is an algebraic structure where the operations addition and multipli- cation are defined in such a way that they work similarly to the arithmetics on the integers.

Definition 1. A ring is an abelian group hR, +i together with an operation · called multiplication and an identity element 1, satisfying the following con- ditions for all a, b, c ∈ R:

1. a · (b · c) = a · b · (c) (associativity)

2. a · (b + c) = a · b + a · c

3. (b + c) · a = b · a + c · a (distributivity)

4. 1 · a = a · 1 = 1 (identity)

If the multiplication operation is commutative, the ring is said to be a commutative ring. Usually, the multiplication sign is omitted, so that e.g.

a · b is written ab.

In the following, all rings will be considered to be commutative.

A paradigmatic example of a commutative ring is the set of integers Z together with the usual operations of addition and multiplication. Another example of a ring, prefiguring the discussion in section 1.3, is the ring R[X]

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of polynomial functions in one variable p(x) on the real numbers R, with addition and multiplication defined as usual in calculus: (p + r)(x) = p(x) + r(x), and (pr)(x) = p(x)r(x). The identity element is the constant function p(x) = 1.

It is easily seen that this satisfies the axioms of associativity, distributivity and commutativity.

Definition 2. An ideal in a commutative ring R is a non-empty subset I ⊆ R such that I is closed under addition and rx ∈ I for all x ∈ I and all r ∈ R.

An example of an ideal in Z is the set 6Z consisting of all numbers divisible by 6.

An example of an ideal in R[X] is the set of polynomial functions with only powers greater or equal than l of the variable, together with the 0- element. All elements except for 0 may be written p(x) = Pn

i=laixi, with a ∈ R. With r(x) = Pn

j=lbjxj we have that (p + r)(x) = p(x) + r(x) = Pn

k=l(ak+ bk)xk, so the set is closed under addition. With h(x) =Pm j=0cjxj we have (f h)(x) = f (x)h(x) = Pm+n

k=l (P

i+j=kaicj)xk, so the set is closed under multiplication with elements of R[X].

In the following, ideals will frequently be identified by their generating sets.

Definition 3. An ideal I on a ring R is said to be generated by a subset S if every element a ∈ I can be written on the form a = Pn

i=1siri, with each si ∈ S and each ri ∈ R.

An ideal is principal if it can be generated by one element.

The ideals which we are going to investigate will in general be finitely generated ideals, that is, ideals generated by finite subsets. It is then some- times convenient to write I = Rhs1, s2, . . . , sni for the ideal generated by the subset S = {s1, s2, . . . , sn} of the ring R. When there is no doubt as to which ring is intended, we will in the following use the simplified notation hs1, s2, . . . , sni for the ideal generated by the subset.

It is possible to define various operations on ideals, such that the resulting set is also an ideal.

Proposition 1. Let I and J be ideals on a commutative ring R. Then the following operations on ideals give rise to an ideal:

(i) The intersection I ∩ J .

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(ii) The sum I + J = J + I = {a + b | a ∈ I ∧ b ∈ J }.

(iii) The product IJ = J I = {Pn

i=1aibi| ai ∈ I ∧ bi ∈ J}.

(iv) The quotient ideal I : J = {r ∈ R | rb ∈ I for all b ∈ J }.

(v) The radical√

I = {x ∈ R | xn∈ I for some n ≤ 1}.

Proof. (i) In the intersection case, any elements a and b of I ∩ J will be elements of both I and J . Since these are ideals, they are closed under addition, so the sum a + b will be an element of both I and J as well, and consequently of I ∩ J . Similarly, the product ra of any element r ∈ R with any element a ∈ I ∩ J will be in I ∩ J , since it must be in I and J , because these are ideals.

(ii) In the sum case, let a, c ∈ I and b, d ∈ J , so that a + b ∈ I + J and c + d ∈ I + J . Then (a + b) + (c + d) = (a + c) + (b + d) because of associativity and commutativity, and since a + c ∈ I and b + d ∈ J , (a + c) + (b + d) ∈ I + J . With r ∈ R, we have from distributivity that r(a + b) = ra + rb ∈ I + J , since ra ∈ I and rb ∈ J .

(iii) Let r, s ∈ IJ with r = Pn

i=1aibi and s = Pn+m

i=n+1aibi, such that all ai ∈ I and all bi ∈ J. Then r + s =Pn+m

i=1 aibi, and since all ai ∈ I and all bi ∈ J, r + s ∈ IJ. Furthermore, let t ∈ R. Then, tr = tPn

i=1aibi = Pn

i=1(tai)bi. Since I is an ideal in R, all tai ∈ I, so tr ∈ IJ.

(iv) Let r, s ∈ I : J . Then, from distributivity, (r + s)b = rb + sb ∈ I for all b ∈ J , since rb ∈ I for all b ∈ J and sb ∈ I for all b ∈ J , so r + s ∈ I : J . Let t ∈ R. Then (tr)b = t(rb) ∈ I for all b ∈ J , since rb ∈ I for all b ∈ J and I is an ideal in R.

(v) Let r, s ∈ √

I, with rn ∈ I and sm ∈ I. Then, the binomial theorem gives that (r + s)m+n = Pm+n

k=0 m+n

k rksm+n−k ∈√

I. This is because for all k, either k ≥ m or m + n − k > m + n − m = n, so each term in the sum will have one factor in I and the other factors in R. Let t ∈ R.

Then, since R is commutative, rn ∈ I, and tn ∈ R, (tr)n = tnrn ∈ I.

Thus, tr ∈√ I.



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This essay will be primarily concerned with products and the special case of powers of ideals. If I is an ideal in a commutative ring, its n-th power In = {a1a2· · · an| a1, a2, . . . , an∈ I}.

The concept of an ideal allows us to define an important kind of ring, the quotient ring.

Definition 4. For an ideal I on a commutative ring R, we may define the relation ∼: a ∼ b iff a − b ∈ I. The equivalence class with respect to the relation ∼ of an element a ∈ R is [a] = {a + r : r ∈ I}. The quotient ring R/I consists of the set of such equivalence classes of elements of R, with addition on R/I defined as [a] + [b] = [a + b] and multiplication defined as [a][b] = [ab].

For example, for the ring of integers Z and the ideal 6Z, the quotient ring Z/6Z = {[0], [1], [2], [3], [4], [5]}.

For section 3, we will need the concepts of maximal and primary ideals.

Definition 5. Let R be a ring. An ideal I ( R is maximal if there is no ideal J in R such that I ( J ( R.

Definition 6. An ideal I ⊆ R is primary if I 6= R and, for every x, y ∈ R, xy ∈ I implies that x ∈ I or yn∈ I for some n > 0.

Furthermore, if√

I = m, where m ⊆ R is a maximal ideal, then I is said to be m-primary. [4][p. 275]

The ideal 9Z (generated by a prime power) is a primary ideal. Assume that an element a ∈ 9Z is written a = xy. Then either 9|x, in which case x ∈ I, 9|y, in which case y1 ∈ I, or 3|x and 3|y, in which case y2 ∈ I. 9Z is also a 3Z-primary ideal, since√

9Z = 3Z, which is maximal.

The ideal 6Z is not a primary ideal, since e. g. the element 6 may be written 6 = 2 · 3, with 2 6∈ 6Z and 3n 6∈ 6Z for any n > 0. Notice that

√6Z = 6Z, which is not maximal, so 6Z is also not m-primary for any m.

1.2 Modules

Modules will be important for the discussion in the third section of this thesis.

The notion of a module is a generalization of the notion of a vector space.

The main difference between modules and vector spaces is that the scalars of a module need only form a ring, whereas the scalars of a vector space must form a field.

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Definition 7. Let R be a commutative ring. An R-module M on a consists of an abelian group M with an operation · : R × M → M satisfying the following conditions for all x, y ∈ M and for all r, s ∈ R:

1. r · (x + y) = r · x + r · y 2. (r + s) · x = r · x + s · x 3. (rs) · x = r · (s · x)

4. 1R· x = x, where 1R is the multiplicative identity of the ring.

The ring R itself is always an R-module. (This follows from the definition of a ring.)

Ideals and quotient rings of a ring R may be considered as modules over R. For instance, the ideal 6Z of Z and the quotient ring Z/6Z = {[0], [1], [2], [3], [4], [5]} are modules over Z.

Another example of a module is the vector space of Euclidean vectors (ordered triples) (a, b, c) in R3 over the field of real numbers R.

Definition 8. Let R be a commutative ring, M be an R-module and N be a subgroup of M . Then N is a R-submodule of M if, for any x ∈ N and r ∈ R, r · x ∈ N .

For example, the subgroup 12Z of the ideal 6Z seen as a module over Z is a submodule, since it is an additive subgroup which is also an ideal over Z.

As in the case of rings, it is possible to construct quotient modules.

Definition 9. For a submodule N of a module M over a commutative ring R, we may define the relation ∼: a ∼ b iff a − b ∈ N . The equivalence class with respect to the relation ∼ of an element a ∈ M is [a] = {a + r : r ∈ N }.

The quotient module M/N consists of the set of such equivalence classes of elements of M , with addition on M/N defined as [a]+[b] = [a+b] and module multiplication with elements of R defined as r[a] = [ra], for all a, b ∈ M and r ∈ R.

An example is the quotient module 6Z/12Z = {[0], [6]} over Z.

Definition 10. The length ` of a module is the length of its longest chain of proper submodules.

For example, the length of the quotient ring Z/6Z seen as a module over Z is 2, since the proper submodules (ideals) of Z/6Z are {[0], [2]} and {[0], [3]}, and neither of these submodules has any other proper submodule than the zero module {[0]}.

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2 Monomial ideals and conditions on their powers and products

This section contains the main results of the thesis. In the first subsection, we explain what monomial ideals on polynomial rings are, how they can be graphically represented, and what it means for their powers and products to have forms which can be graphically represented as repeated staircases. Most of the definitions here will follow Moore, Rogers and Wagstaff in [2]. In the second subsection, we find conditions on ideals for their graphical represen- tations of their powers to take such shapes, and in the third subsection, we find corresponding conditions on powers. Some of these results are special cases in the polynomial ring K[x, y] of Veronica Crispin Quino˜nez’ results in [3].

2.1 Polynomial rings and monomial ideals

This essay is concerned with a special kind of ring, called a polynomial ring.

These rings are formed from sets of polynomials with coefficients in a ring or a field. In the following, we will only consider polynomial rings with coefficients in fields. A polynomial ring in several variables K[x1, . . . , xn] over a field K is an extension of K, called the coefficient field, with the elements x1, . . . , xn. These elements are external to K and commute with each of its elements.

Monomials (short for mononomials) are polynomials with only one term.

Hence, on a polynomial ring K[x1, . . . , xn], a monomial is an element of the ring of the form a0Qn

k=1xmkk, with a0 ∈ K and mk ∈ N0 for each k. An example is the monomial 5.7x41x3 on R[x1, x2, x3].

In this thesis, we will focus primarily on the polynomial ring in two vari- ables K[x, y].

The question of whether a polynomial divides another will be important in the following.

Definition 11. Let ¯u = u0Qn

k=1xakk and ¯v = v0Qn

k=1xbkk be monomials.

Then ¯u is said to divide ¯v if ak ≤ bk for all k. In that case, the quotient

¯ v

¯ u = vu0

0

Qn

k=1xbkk−ak.

For example, the monomial 12y4x3on K[x, y] divides the monomial 36y4x6, and the quotient 36y12y44xx63 = 3x3.

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Definition 12. An ideal in the polynomial ring K[x1, ..., xn] is called mono- mial if it is generated by monomials.

We notice that a monomial is redundant in the generating set of an ideal if some other monomial in the generating set divides it. For instance, in the generating set y3, x2y2, x3y3, x4y, x5 the monomial x3y3 is redundant, since it is divisible by x2y2. Since the divisibility relation is antisymmetric, there is never more than one way of removing all redundant monomials from a gen- erating set which consists only of monomials. It follows that each monomial ideal has a unique minimal generating set of monomials.

The same ideal may, however, be generated by different minimal sets of polynomials. For instance, the monomial ideal hy3, x2i may also be generated by the sequence y3, x2+ y3 or the sequence 2x2+ y3, x2.

In the second section of this thesis, it will be important that the products of two generating sets ST = {st | s ∈ S, t ∈ T } will be a generating set for the product of the ideals generated by each set.

Theorem 2. Let I and J be two ideals on a ring R, and S and T their respective generating sets. Then the set ST is a generating set of the product of ideals IJ , that is, IJ = hST i.

Proof. Let aα = Pn

0 sipi, si ∈ S, pi ∈ R be some element in I, and bα = Pm

0 tjqj, tj ∈ S, qj ∈ R be some element in J. Then we have the product aαbα = Pm+n

k=0 (P

i+j=ksipitjqj) = Pm+n k=0 (P

i+j=ksitjpiqj). Since P

i+j=ksitjpiqj is a linear combination of elements on the form sitjpiqj, with sitj ∈ ST and piqj ∈ R, it is an element of hST i for each k. But then aαbα = Pm+n

k=0 (P

i+j=ksitjpiqj) is a finite sum of elements of hST i, so it is an element of hST i for each α. Then we in turn have that Pn

α=0aαbα is a finite sum of elements of hST i, so it is also an element of hST i. But IJ is precisely the set of such sums, so IJ ⊆ hST i.

Conversely, let rst, r ∈ R, st ∈ ST be some element of hST i. Since s ∈ I and t ∈ J , st ∈ IJ , and since IJ is an ideal in R, rst ∈ IJ . Therefore,

hST i ⊆ IJ. 

This is very useful for monomial ideals, which have minimal generating sets of monomials, since it means that we can find and denote the product of two monomial ideals by multiplying pairwise the monomials of the generating sets.

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Example 1. The product of I = hy3, x3y2, x4i och J = hy6, x2y4, x4y, x5i in K[x, y] is IJ = hy9,

x3y8,

x4y6i + hx2y7,

x5y6,

x6y4i + hx4y4,

x7y3, x8yi + hx5y3,

x8y2, x9i = hy9, x2y7, x4y4, x5y3, x8y, x9i.

The square of L = hy3, x2y2, x4y, x5i is L2 = LL = hy6, x2y5, x4y4, x5y3, x6y3, x7y2, x8y2, x9y, x10i = hy6, x2y5, x4y4, x5y3, x7y2, x9y, x10i.

Monomial ideals in polynomial rings may be graphically represented by sets of ordered n-tuples of natural numbers.

Definition 13. The graph Γ of a monomial ideal I in the polynomial ring K[x1, . . . , xn] is Γ(I) = {(a1, . . . , an) ∈ Nn|Qn

k=1xakk ∈ I}.[2, p. 5]

Since the monomial ideal contains all monomials with exponents of the respective variables larger than the corresponding exponents of the monomi- als in the generating set, the following notation is helpful: [(a1, . . . , an)] = {(b1, . . . , bn) ∈ Nn|bk ≥ ak for all k}.

The graph of a monomial ideal I on K[x, y] may be easily visualized in a two-dimensional diagram.

Example 2. The monomial ideal I = hx2y4, x4y3, x6y2, x7yi in K[x, y] has the graph Γ(I) = [(2, 4)] ∪ [(4, 3)] ∪ [(6, 2)] ∪ [(7, 1)]. Notice that the mono- mials with the highest y-exponents are written first, which makes it easier to compare the graph Γ(I) with the following visual representation:

x 7

6 5 4 3 2 1 0 y

4 3 2 1 0

t

t

t t

We notice that the graph has the shape of a staircase.

In certain cases , the graph of the square of the ideal will have the same staircase shape, repeated twice and translated to the double distance from

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the y-axis and the x-axis, respectively. This happens to be the case with the ideal I above. We have that I2 = hx4y8, x6y7, x8y6, x9y5, x11y4, x13y3, x14y2i.

This square ideal is represented by the following diagram:

x 14

13 12 11 10 9 8 7 6 5 4 3 2 1 0 y

8 7 6 5 4 3 2 1 0

t

t

t t

t

t t

We notice that the ideal I may be written I = x2yhy3, x2y2, x4y, x5i, and, correspondingly, that I2 = x4y2hy6, x2y5, x4y4, x5y3, x7y2, x9y, x10i. This means that squaring the ideal will, in effect, do two things: translate it by the vector corresponding to the exponents of the common factor, and create new points on (or outside) the new staircase graph by multiplying the monomials with each other. In the second respect, the original monomial ideal will behave identically to a monomial ideal generated by the set formed by dividing the minimal generating set of the original ideal by its greatest common factor.

Example 3. We may compare the graphs of I and I2 to the graphs of the ideal J = hy3, x2y2, x4y, x5i, with the common factors of the generating set of I quotiented out. Γ(J ) = [(0, 3)] ∪ [(2, 2)] ∪ [(4, 1)] ∪ [(5, 0)]. This is rep- resented by the following diagram:

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x 5 4 3 2 1 0 y 3 2 1 0

t

t

t t

Squaring J , we get J2 = hy6, x2y5, x4y4, x5y3, x6y3, x7y2, x8y2, x9y, x10i

= hy6, x2y5, x4y4, x5y3, x7y2, x9y, x10i. This square ideal is represented by the following diagram:

x 10

9 8 7 6 5 4 3 2 1 0 y 6 5 4 3 2 1 0

t

t

t t

t

t t

We will in the following only study ideals with no common factors in the minimal generating set. Any such ideal can be written on the form I = hybn, xa1ybn−1, . . . , xan−1yb1, xani.

Similarly to the case of powers, the graphs of some products of two dif- ferent ideals have the shape of the graph of one of the ideals followed by the graph of the other ideal.

Example 4. Let I = hy7, xy6, x2y4, x3y2, x4i and J = hy5, x2y4, x4y3, x6y2, x8y, x9i be ideals on K[x, y]. Then their product is IJ = hy12, xy11, x2y9, x3y7, x4y5, x6y4, x8y3, x10y2, x12y, x13i. This is represented in the following diagram:

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x 13 12 11 10 9 8 7 6 5 4 3 2 1 0 y 12 11 10 9 8 7 6 5 4 3 2 1 0

t t

t t

t t

t

t

t

t t t

t t

t

tt

t

t

t

t t

I

J IJ

The aim of this paper is to discover conditions for the n-th power of an ideal or the product of two ideals to be equal to the ideal represented by the corresponding repeated staircase graph.

Definition 14. (a) Let I be a monomial ideal in K[x, y], and assume that yB and xA belong to its minimal generating set of monomials, with yB the monomial with the largest y-exponent and xA the monomial with the largest x-exponent. Then we define the r-th staircase Tr(I) of order r of an ideal I and its powers Ir as Tr(I) = IhyB, xAir−1.

Alternatively, we may write:

T1(I) = I, T2(I) = hyBT1, xAT1(I)i, T3(I) = hyBT2(I), xAT2(I)i, . . . or T1(I) = I, T2(I) = hyBI, xAIi, T3(I) = hy2BI, xAyBI, x2AIi, . . .

(b) Let I and J be monomial ideals on K[x, y]. Assume that yB and xA belong to the minimal generating set of I, and that yD and xC belong to the minimal generating set of J . Then we define the staircase T (I, J ) = hyDI, xAJ i, and the staircase TJ I = hyBJ, xCIi.

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Example 5. (a) Consider the ideal I = hyb, . . . , xai = hy3, x2y2, x4y, x5i.

We have that T1(I) = I, T2(I) = hyb, xaiI, and T3(I) = hy2b, xayb, x2aiI.

These staircase ideals are shown in the figure below:

x 15

10 9 8 7 6 5 4 3 2 1 0 y 9 8 7 6 5 4 3 2 1 0

t

t

t t I

t

t

t ybI

t

t

t t xaI

t

t

t y2bI

t

t xaybI t

t

t

t t x2aI

t

t

t

(b) With the ideals I = hy7, xy6, x2y4, x3y2, x4i and J = hy5, x2y4, x4y3, x6y2, x8y, x9i from Example 3, IJ = J I = T (I, J ) = hy12, xy11, x2y9, x3y7, x4y5, x6y4,

x8y3, x10y2, x12y, x13i.

For comparison, in this case T (J, I) = hy12, x2y11, x4y10, x6y9, x8y8, x9y7, x10y6, x11y4, x12y2, x13i, which is represented by the following diagram:

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x 13 12 11 10 9 8 7 6 5 4 3 2 1 0 y 12 11 10 9 8 7 6 5 4 3 2 1 0

t t

t t

t t

t

t

t

t t t

t

t

t

t tt

t t

t t I

J IJ

2.2 Powers of monomial ideals

In the first part of this section, we will study powers of a single ideal. We want to discover conditions, under which I satisfies the formula

Ir = Tr(I) (*).

We start with the following result:

Theorem 3. If I2 = T2(I), then Ir = Tr(I) for all r.

Proof. We use induction on r. The base case is: I3 = II2 = IT2(I) = IhyBI, xAIi = hyBI2, xAI2i = hyBT2(I), xAT2(I)i = T3. Now suppose that Ir−1 = Tr−1(I). Then Tr(I) = hyBTr−1(I), xATr−1(I)i = hyBIr−1, xAIr−1i = hyBIIi−2, xAaIIr−2i = Ir−2hyBI, xAIi = Ir−2T2(I) = Ir−2I2 = Ir.  To find conditions on the shape of an ideal to satisfy (*), we turn to a basic consideration of symmetry. We expect ideals whose graphs have the same shape but different scales to behave identically.

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Example 6. We compare the ideal J = hy3, x2y2, x4y, x5i of Example 3 with the ideal L = hy9, x6y6, x12y3, x15i, where all the exponents of the monomials of J have been multiplied by three:

x 5 4 3 2 1 0 y 3 2 1 0

t

t

t t

x 15 12 9 6 3 0 y 9 6 3 0

t

t

t t

J L

We have J2 = hy6, x2y5, x4y4, x5y3, x6y3, x7y2, x8y2, x9y, x10i

= hy6, x2y5, x4y4, x5y3, x7y2, x9y, x10i, and similarly L2 = hy18, x6y15, x12y12, x15y9, x21y6, x27y3, x30i:

x 10 9 8 7 6 5 4 3 2 1 0 y 6 5 4 3 2 1 0

t

t

t t

t

t t

x 30 27 24 21 18 15 12 9 6 3 0 y 18 15 12 9 6 3 0

t

t

t t

t

t t

J2 L2

In general, we may consider ideals I that are created from an ideal J = hybn, ybn−1xa1, . . . , yb1xan−1, xani having the required property, such that I = hykbn, ykbn−1xka1, . . . , ykb1xkan−1, xkani, where k is a positive integer.

Proposition 4. Let I = hykbn, ykbn−1xka1, . . . , ykb1xkan−1, xkani, where k is a positive integer, and J = hybn, ybn−1xa1, . . . , yb1xan−1, xani be ideals such that Ji = Ti(J ) for all i. Then Ir = Tr(I) for all r.

Proof. We want to show that every point in the graph of I2 is also a point in the graph of T2(I). Since the graph of T2(I) contains all points above and to the right of some point in the graph of some generating set of T2(I), it

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suffices to show that each point in the graph of some generating set of I2 lies above and to the right of some point in the graph of some generating set of T2(I). Formally, the condition is that for each monomial yk(bn−i+bn−j)xk(ai+aj) in the generating set of I2, there is some monomial yDxC in the generating set of T2(I) such that k(ai+ aj) ≥ c and k(bn−i+ bn−j) ≥ d.

If i+j ≤ n, we consider the element yk(bn+bn−l)xkal such that bn−i+bn−j ≥ bn+ bn−l and ai+ aj ≥ al. Such an element exists since Ji = Ti(J ) for all i.

Then, k(ai+ aj) ≥ k(bn+ bn−l) and k(bn−i+ bn−j) ≥ kal.

If i+j > n, we consider the element yk(bn−l)xk(an+al)such that bn−i+bn−j ≥ bn−l and ai+ aj ≥ an+ al. Such an element exists since Ji = Ti(J ) for all i.

Then, k(bn−i+ bn−j) ≥ kbn−l and k(ai+ aj) ≥ k(an+ al).  We continue by finding classes of ideals that satisfy Ii = Ti(I). A simple case is given by ideals on the form hyb, xai.

Proposition 5. Let I = hyb, xai ⊆ K[x, y]. Then Ir = Tr(I) for all r.

Proof. We have Ii = hyb, xaii = Ihyb, xaii−1= Ti(I).  An example is the ideal I = hy, x2i. We may follow how the powers of I have staircase graphs with an increasing number of repetitions of the same kind of step (height 1, length 2) in this diagram:

x 14 13 12 11 10 9 8 7 6 5 4 3 2 1 0 y

7 6 5 4 3 2 1 0

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Proposition 5 may be generalized by considering ideals of the form I = hxA, yBin. We notice that ideals of this type correspond to staircase graphs where all the steps have the same size.

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Corollary 6. If I = hyb, xain, then Ir = Tr(I) for all r.

Proof. I = hyb, xain= hybn, xayb(n−1), . . . , xa(n−1)yb, xani.T2(I) = hybnI, xanIi = hy2bn, xayb(2n−1), . . . , xa(n−1)yb(n+l), xanybn, xa(n+1)yb(n−1), . . . , xa(2n−1)yb, x2ani.

An arbitrary element in the generating set of I may be written as xaiyb(n−i), with 0 ≤ i ≤ n. This means that every element in the generating set of I2 may be written xaiyb(2n−i)xajybj(2n−j)= xa(i+j)yb(2n−i−j), with 0 ≤ i ≤ n, 0 ≤ j ≤ n, i ≤ j, but if we write i + j = k it is obvious that xakybk(2n−k) is an element in the generating set of T2(I). By Theorem 3 above, this means that

Ir = Tr(I) for all r. 

In Proposition 5, we saw that a certain class of ideals satisfies (*), and in Corollary 6, we saw that powers of ideals in this class also satisfy (*). It can actually be shown that if any ideal satisfies (*), then powers of that ideal also satisfy (*).

Theorem 7. Let I be a monomial ideal such that Ir = Tr(I) for all r. Then the ideal J = Ik is such that Jr = Tr(J ) for all r.

Proof. We have that I2 = Ihyb, xai, with a = A and b = B from Definition 14. Then J2 = (Ik)2 = (I2)k, and by the assumption, (I2)k = Ikhyb, xaik. We want to show that this is equal to T2(J ) = Ikhybk, xaki.

We have that T2(J ) = Ikhybk, xakiassump.= Ihyb, xaik−1hybk, xaki = Ihyb, xaik−1hybk, xaki = Ihyb(k−1), xayb(k−2), . . . , xa(k−2)yb, xa(k−1)ihybk, xaki = hyb(2k−1), xayb(2k−2), . . . ,

xa(k−1)ybk, xakyb(k−1), . . . , xa(2k−2)yb, xa(2k−1)i = Ihxayb, i2k−1 assump.= Ikhyb, xaik = J2, by the above. Hence T2(J ) = J2and the result follows by Theorem 3. 

There is also another way in which the ideals from Proposition 5 is a special case of a more general class of ideals that possess the required property. In fact, if the width ∆x and the height ∆y of each step of the staircase graph do not increase as x and y (the natural number ex- ponents of the x-part and the y-part of the monomial, respectively) in- crease, the corresponding ideal satisfies Ir = Tr(I) for all r. We may write such an ideal as I = hyb1+...+bn, yb1+...+bn−1xa1, yb1xa1+...+an−1, xa1+...+ani, with a1 ≥ a2 ≥ a3 ≥ . . . ≥ an and b1 ≥ b2 ≥ b3 ≥ . . . ≥ bn.

Theorem 8. Let I = hyb1+...+bn, xa1yb1+...+bn−1, . . . , xa1+...+an−1yb1, xa1+...+ani ⊆ K[x, y] be a monomial ideal, with a1 ≥ a2 ≥ a3 ≥ . . . ≥ an and b1 ≥ b2 ≥ b3 ≥ . . . ≥ bn. Then Ir= Tr(I) for all r.

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Proof. The staircase ideal T2(I) = hy2(b1+...+bn), xa1y2(b1+...+bn−1)+bn, . . . , xa1+...+anyb1+...+bn, x2a1+a2+...+anyb1+...+bn−1, . . . , x2(a1+...+an)i. We want to show that any element of I2 is included in T2(I). An element is included in T2(I) if there, for the corresponding monomial xayb, is some monomial xcyd in the generating set of T2(I) such that a ≥ c and b ≥ d.

An arbitrary element in the generating set of I2 may be written

yb1+...+bn−ixa1+...+aiyb1+...+bn−jxa1+...+aj. We may without loss of generality as- sume that j ≥ i. Then yb1+...+bn−ixa1+...+aiyb1+...+bn−jxa1+...+aj =

y2(b1+...+bn−j)+bn−j+1+...+bn−ix2(a1+...+ai)+ai+1+...+aj. We compare this to the ele- ment in the generating set of T2(I) with the same number i + j of occurrences of as in the exponent of the x-term, and the same number 2(n − j) + n − i − (n − j) = 2n − i − j of bt in the exponent of the y-term.

(i) If i + j < n, the element in T2(I) with the same number of occurrences of asand btin the exponents as the arbitrary element in the generating set of I2 is xa1+...+ai+jy2(b1+...+bn−i−j)+bn−i−j+1+...+bn. We write S1x = 2(a1+ . . . + ai) + ai+1+ . . . + aj for the exponent of the x-term of the I2- element, and S2x = a1+ . . . + ai+j for the exponent of the x-term of the T2(I)-element. If we disregard the common terms a1+ . . . + aj, we are left with the terms a1+ . . . + ai in S1x and the terms aj+1+ . . . + ai+j

in S2x. Since there is an equal number of terms in both sums, and a1 ≥ . . . ≥ ai ≥ . . . ≥ aj+1 ≥ . . . ≥ ai+j, S1x≥ S2x.

Furthermore, we write S1y = 2(b1 + . . . + bn−j) + bn−j+1+ . . . + bn−i

for the exponent of the y-term of the I2-element, and S2y = 2(b1 + . . . + bn−i−j) + bn−i−j+1+ . . . + bn for the exponent of the y-term of the T2(I)-element. Disregarding the common terms b1+ . . . + bn−i, we are left with S1y= bn−i−j+1+ . . . + bn−j, and S2y = bn−j+1+ . . . + bn. Since there is an equal number of terms in both sums, and bn−i−j+1 ≥ . . . ≥ bn−j ≥ bn−j+1 ≥ . . . ≥ bn, S1y ≥ S2y.

(ii) If i + j ≥ n, the element in T2(I) with the same number of occurrences of asand btin the exponents as the arbitrary element in the generating set of I2 is x2(a1+...+ai+j−n)+ai+j−n+1+...+anyb1+...+b2n−i−j. We write S1x= 2(a1 + . . . + ai) + ai+1 + . . . + aj for the exponent of the x-term of the I2-element, and S2x = 2(a1 + . . . + ai+j−n) + ai+j−n+1+ . . . + an for the exponent of the x-term of the T2(I)-element. If we disregard the common terms 2(a1+ . . . + ai+j−n) and ai+1+ . . . + aj, we are left with the terms ai+j−n+1+ . . . + ai in S1x and the terms aj+1+ . . . + an

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in S2x. Since there is an equal number of terms in both sums, and ai+j−n+1 ≥ . . . ≥ ai ≥ . . . ≥ aj+1 ≥ . . . ≥ an, S1x≥ S2x.

Furthermore, we write S1y = 2(b1+. . .+bn−j)+bn−j+1+. . .+bn−ifor the exponent of the y-term of the I2-element, and S2y = b1+ . . . + b2n−i−j for the exponent of the y-term of the T2(I)-element. Disregarding the common terms b1+ . . . + bn−i, we are left with S1y = b1+ . . . + bn−j, and S2y = bn−i+1+ . . . + b2n−i−j. Since there is an equal number of terms in both sums, and b1 ≥ . . . ≥ bn−j ≥ . . . ≥ bn−i+1 ≥ . . . ≥ b2n−i−j, S1y ≥ S2y.

We thus have that, for an arbitrary monomial xayb of the generating set of I2, there is some monomial xcyd in the generating set of T2(I) such that a ≥ c and b ≥ d. This means that I2 ⊆ T2(I). Obviously, T2(I) ⊆ I2, so I2 = T2(I). By Theorem 3 above, we then have Ir = Tr(I) for all r.  Example 7. Consider the ideal I = hy6, x4y5, x6y4, x8y2, x9i, which has steps of non-increasing width from the left and of non-increasing height from below.

The figure below shows, in red, green, and yellow, the points of the graph corresponding to monomials in the generating set of I2. All these points are also inside the area representing T2, because of the shape of I.

x 18

9 8 7 6 5 4 3 2 1 0 y 12 11 10 9 8 7 6 5 4 3 2 1 0

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Another group of ideals that satisfy (*) may be called line ideals. An ideal is a line ideal if its graph is given by the points with integer coordinates on a straight line between points (0, y) and (x, 0) or to the right of and above the line.

Before we define the line ideals, we need the notion of x-tight and y-tight ideals. The following definition originates from Definition 2.1 in [3].

Definition 15. Let I be a monomial ideal in K[x,y]. Let A be the largest x-exponent of any monomial in the minimal generating set of monomials of I, and B be the largest y-exponent. I is said to be x-tight if every integer between 0 and A is represented as the x-exponent of some monomial in the minimal generating set. Similarly, I is said to be y-tight if every integer between 0 and B is represented as the y-exponent of some monomial in the minimal generating set.

We can now define the line ideals. The definition given here corresponds to that of simple integrally closed ideals in [3].

Definition 16. Let I be a monomial ideal. Assume that I = hybn, xa1ybn−1, . . . , xan−1yb1, xani, with bn−i≥ bnban

nai such that each bn−i is a positive integer, I is y-tight if bn ≥ an, I is x-tight if an ≥ bn, ai − an+ abn

nbn−i < 1, and bn−i− bn+ ban

nai < 1. Then we call I a line ideal.

Theorem 9. Let I be a line ideal. Then Ir = Tr(I) for all r.

Proof. We notice that the graph of T2(I) will be delimited to the left and be- low by a line with the same slope −ban

n as the line delimiting the ideal, running from (0, 2bn) to (2an, 0). The equation of this line is y = 2bnban

nx. Since the graph of T2(I) contains two copies of the graph of I that have only been translated by an integer vector, the graph of T2(I) will contain all points with integer coordinates to the right and above its delimiting line. Formally, we have T2(I) = hy2bn, xa1ybn+bn−1, . . . , xanybn, xan+a1ybn−1, . . . , x2ani. We add bn to both sides of the inequality bn−i ≥ bnabn

nai to get bn+ bn−i≥ 2bnban

nai, so all points in the left half of the graph of T2(I) lie above and to the right of the delimiting line. If we instead add an to the inequality written as ai ≥ anabn

nbn−i, we get an+ ai ≥ 2anabn

nbn−i, or bn−i≥ 2bnban

n(an+ ai), so all points in the right half of the graph of T2(I) lie above and to the right of the delimiting line. Since ai− an+abn

nbn−i ≤ 1, an+ ai− 2an+abn

nbn−i ≤ 1.

Similarly, bn+ bn−i− 2bn+ abn

nai ≤ 1, so the points in the generating set of

References

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