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Volume 32, No. 1, pp. 21-35, January 2006

COMPACTNESS OF THE HARDY OPERATOR AND ITS LIMITING CASE

BY

AMIRAN GOGATISHVILI, ALOIS KUFNER, LARS-ERIK PERSSON AND ANNA WEDESTIG

Abstract. Let 1 < p ≤ q < ∞. Inspired by some recent results concerning Hardy type inequalities where the equivalence of four scales of integral conditions is proved, we use related ideas to prove some new compactness results for the Hardy operator, and we give the corresponding scales for the P´olya-Knopp inequality.

1. Introduction

We consider the general one-dimensional Hardy inequality

Z b

0

Z x

0

f (t)dtqu(x)dx1/q ≤ C Z b

0

fp(x)v(x)dx1/p (1.1) with a fixed b, 0 < b ≤ ∞, for measurable functions f ≥ 0, weights u and v and for the parameters p, q satisfying

1 < p ≤ q < ∞.

In [2] the equivalence of four scales of integral conditions that characterize the inequality (1.1) and give conditions with the usual Muckenhoupt condition as a special case was proved. The proof was carried out by first proving an equivalence theorem of independent interest that also will be applied in this paper. We therefore recall the equivalence theorem (see Theorem 2.1 in [2]):

Received July 2, 2004; revised February 8, 2005.

AMS Subject Classification. Primary 26D10, 26D15; secondary 47B07, 47B38.

Key words. Hardy operator, compactness, Hardy’s inequality, Polya-Knopp’s inequality, Lorentz space.

This paper is in final form and no version of it will be submitted for publication elsewhere.

21

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Theorem 1.1. For −∞ ≤ a < b ≤ ∞, α, β and s positive numbers and f , g measurable functions positive a.e. in (a, b), let us denote

F (x) :=

Z b

x

f (t)dt, G(x) :=

Z x

a

g(t)dt (1.2)

and

B1(x; α, β) := Fα(x)Gβ(x);

B2(x; α, β, s) :=Rxbf (t)Gβ−sα (t)dtαGs(x);

B3(x; α, β, s) :=

 Rx

a g(t)Fα−sβ (t)dt

β

Fs(x);

B4(x; α, β, s) :=Raxf (t)Gβ+sα (t)dtαGs(x);

B5(x; α, β, s) :=

 Rb

xg(t)Fα+sβ (t)dt

β

Fs(x).

(1.3)

The numbers B1 := supa<x<bB1(x; α, β) and Bi(s) = supa<x<bBi(x; α, β, s) (i = 2, 3, 4, 5) are mutually equivalent. The constants in the equivalence relations can depend on α, β and s.

The main result of this paper can be found in Section 2 where we use related ideas to prove some new scales of compactness results for the Hardy operator which complement the classical criterion (see (2.7)). In Section 3, we derive some scales of weight characterizations for the P´olya-Knopp inequality, analogous to that of Theorem 1.1.

2. Compactness Results

In the paper [4] some criteria of the continuity of the Hardy operator H : (Hf )(x) =

Z x

0

f (t)dt, (2.1)

as a mapping from Lp(v) = Lp(v; 0, b) into Lq(u) = Lq(u; 0, b) have been derived with 0 < b ≤ ∞ and

Lr(w) :=nf ≥ 0; kf kr,w:= Z b

0 fr(t)w(t)dt1/r < ∞o.

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Here r > 1, 1 < p ≤ q < ∞, and u, v, w are given weight functions (i.e. measur- able and positive a.e. in (0, b)).

Let us denote U (x) =

Z b

x u(t)dt, V (x) = Z x

0 v1−p0(t)dt, p0 = p

p − 1. (2.2) We assume throughout the paper, that

U (x) < ∞ and V (x) < ∞ (2.3) for a.e. x ∈ (0, b). On the other hand it is allowed (and this is in fact the more interesting case) that either

U (0) = ∞ (i.e. u /∈ L1(0, b)) (2.4) or

V (b) = ∞ (i.e. v1−p0 ∈ L/ 1(0, b)). (2.5) The necessary and sufficient condition for the continuity of H is the finiteness of the suprema (on (0, b)) of any of the following functions

A1(x) := U1/q(x)V1/p0(x),

A1(x; s) :=Rxbu(t)Vq(p01s)(t)dt1/qVs(x), s > 0, A2(x; s) :=R0xu(t)Vq(p01+s)(t)dt1/qVs(x), s > 0, A3(x; s) :=R0xv1−p0(t)Up0(1qs)(t)dt1/p

0

Us(x) s > 0, A4(x; s) :=Rxbv1−p0(t)Up0(1q+s)(t)dt1/p

0

Us(x) s > 0.

(2.6)

Notice that

(i) A1(x) = A1(x;p10) = A3(x;1q);

(ii) A3(x; s) and A4(x; s) are the ”dual” expressions to A1(x; s) and A2(x; s), respectively;

(iii) A1(x) is the usual ”Muckenhoupt function” AM(x) and A2(x;1p) is the

”Persson-Stepanov function” AP S(x) (and for p = q the ”Tomaselli func- tion” AT(x)).

According to [7, Theorem 7.11], the operator H is compact if and only if

x→0+lim A1(x) = lim

x→b−A1(x) = 0 (2.7)

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and in [4, Theorems 3.1 and 3.2], it was shown that for 0 < s < 1p, H is compact if and only if

x→0+lim Ai(x, s) = lim

x→b−Ai(x, s) = 0, i = 1, 3. (2.8) But since the continuity of H takes place for all s > 0, we can repeat almost literally the proof of Theorems 3.1 and 3.2 in [4] and hence extend the criterion (2.8) to a bigger scale of s, namely to s ∈ (0, ∞) :

Theorem 2.1. The Hardy operator is compact if and only if the function A1(x; s) and/or the function A3(x; s) has zero limits at x = 0 and x = b for any s > 0.

An analogue of Theorem 2.1 using the function A2(x; s) and/or A4(x; s) does not hold. This follows from the example given in [4] where − for some particular weights u, v for which H is compact − it was shown that A2(x;1p) tends to zero for x → 0+, but

x→b−lim A2(x;1 p) 6= 0.

This observation is confirmed also by Example 2.1 below, but first let us mention one obvious result.

Corollary 2.2. Suppose that the weight functions u and v1−p0 are integrable over the whole interval (0, b) (i.e. u, v1−p0 ∈ L1(0, b)). Then the Hardy operator H is compact.

Proof. Since U (0) < ∞ and V (b) < ∞, and since U (b) = 0 and V (0) = 0, we have that A1(0) = A1(b) = 0 and the proof follows by using criterion (2.7).

Example 2.1. (i) Suppose that the Hardy operator is compact and v1−p0 ∈ L1(0, b), i.e. V (b) < ∞ (and, of course, V (b) > 0). Then

x→b−lim A2(x; s) = Z b

0 u(t)Vq(

1 p0+s)

(t)dt1/qVs(b) and hence

x→b−lim A2(x; s) 6= 0.

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(ii) Suppose that the Hardy operator is compact and u ∈ L1(0, b), i.e. U (0) <

∞. Then

x→0+lim A4(x; s) = Z b

0

v1−p0(t)Up0(1q+s)(t)dt1/p

0

Us(0) 6= 0.

On the other hand, we can extend Theorem 2.1 to A2(x; s) supposing that V (b) = ∞, and to A4(x, s) supposing that U (0) = ∞. But for this purpose, we must introduce some notation and modify the criteria of compactness.

Let us denote

U (y, α) :=

Z α

y u(t)dt, V (β, y) :=

Z y

β v1−p0(t)dt. (2.9) Hence it is U (x) = U (x, b), V (x) = V (0, x).

Further denote

A1(y; α, β) := U1/q(y, α)V1/p0(β, y), (2.10) so that

A1(x) = A1(x; b, 0).

Compactness according to R. K. Juberg. Let us denote Jα := sup0<x<αA1(x; α, 0) = sup0<x<αU1/q(x, α)V1/p0(0, x),

Jβ := supβ<x<bA1(x; b, β) = supβ<x<bU1/q(x, b)V1/p0(β, x). (2.11) Supposing that the Hardy operator H is bounded (i.e. continuous), R. K. Juberg [1] has shown, that H is compact if and only if

α→0+lim Jα+ lim

β→b−Jβ = 0. (2.12)

First, let us show that according to (2.3), the assumption about the boundedness of H can be avoided. Indeed, according to (2.12), there exists an α0> 0 such that Jα0 < ∞, and a β0 < b such that Jβ0 < ∞. Due to (2.3), A1(x) is continuous on (0, b) and consequently, bounded on any closed interval [α0, β0] ⊂ (0, b) : A1(x) ≤ C0 for x ∈ [α0, β0]. Moreover, for x ∈ (0, α0]

A1(x) = U1/q(x, b)V1/p0(0, x)

= (U (x, α0) + U (α0, b))1/qV1/p0(0, x)

≤ U1/q(x, α0)V1/p0(0, x) + U1/q0, b)V1/p0(0, x)

≤ Jα0 + U1/q0, b)V1/p0(0, α0) = C1< ∞,

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and similarly we can show that for x ∈ [β0, b), A1(x) ≤ C2 < ∞. Thus H is bounded.

Hence, we have shown that H is compact if and only if (2.12) holds, and using now the equivalence relations described in Theorem 1.1, we are able to rewrite the compactness criteria in terms of the functions A1(x; s ) and A3(x, s).

Namely, if we denote

A1(x; s; α, β) =

Z α

x

u(t)Vq(p01s)(β, t)dt

1/q

Vs(β, x), (2.13) so that

A1(x; s) = A1(x; s; b, 0),

we obtain from Theorem 1.1 that Jα and Jβ are equivalent to J1,α(s) := sup

0<x<αA1(x; s; α, 0) and J1β(s) := sup

β<x<b

A1(x; s; b, β) respectively: It suffices to use the equivalence relations mentioned not for the interval (0, b), but for the interval (0, α) and (β, b), respectively.

In view of the criterion (2.12), we immediately have:

Theorem 2.3. The Hardy operator is compact if and only if

α→0+lim J1,α(s) + lim

β→b−J1β(s) = 0 for any s > 0.

A similar Theorem can be formulated using the function A3(x; s).

If we want to use the functions A2(x; s) and A4(x; s) the situation is a little different, since in the expression for A2(x; s) only the left endpoint (zero) ap- pears explicitly, while in A4(x; s), we have explicitly only the right endpoint b.

Nevertheless, if we proceed analogously as in the foregoing case and denote A2(x; s; α, β) =

Z x

α

u(t)Vq(

1 p0+s)

(β, t)dt

1/q

Vs(β, x) (2.14) so that

A2(x; s) = A2(x; s; 0, 0),

we obtain again according to Theorem 1.1 that Jα and Jβ are equivalent to J2,α(s) := sup

0<x<α

A2(x; s; 0, 0) = sup

0<x<α

A2(x; s) (2.15)

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and

J2β(s) := sup

β<x<b

A2(x; s; β, β),

respectively, where now the parameter α does appear in J2,α(s) only under the suprema sign. The corresponding theorem now states:

Theorem 2.4. The Hardy operator is compact if and only if

α→0+lim J2,α(s) + lim

β→b−J2β(s) = 0 (2.16)

for every s > 0.

Again, a similar theorem could be formulated in terms of A4(x, s), where now

J4,α(s) := sup

0<x<α

Z α

x

v1−p0(t)Up0 1q+s



(t, α)dt

1/p0

U (x, α)s, and

J4β(s) := sup

β<x<b

Z b

x

v1−p0(t)Up0 1q+s

 (t, b)dt

!1/p0

Us(x, b) = sup

β<x<b

A4(x; s).

But on the other hand, we have also the following assertion:

Theorem 2.5. Suppose that v1−p0 ∈ L1(0, b), i.e. V (b) < ∞. Then H is compact if and only if

x→0+lim A2(x; s) = 0 (2.17)

for every s > 0.

Proof. According to (2.15), J2,α(s) = sup0<x<αA2(x; s). If H is compact, then due to (2.16), J2,α(s) → 0 for α → 0, and, consequently, we have (2.17).

Conversely, if (2.17) holds, then J2,α(s) → 0 for α → 0. Since for β fixed, V (β, t) is increasing in t, we have V (β, t) ≤ V (β, x) for t ≤ x, and hence

J2β(s) = sup

β<x<b

Z x

β

u(t)Vq(p01+s)(β, t)dt1/qVs(β, x)

≤ sup

β<x<b

Z b

β

u(t)dt1/qVp01+s(β, x)Vs(β, x)

= Z b

β

u(t)dt1/qV1/p0(β, b),

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and since V (β, b) < V (b) < ∞, J2β(s) → 0 for β → b. Consequently H is compact due to (2.16).

Hence, if v1−p0 is integrable over the whole interval (0, b), we need for the compactness only one of the limits of A2(x; s), and similarly it holds:

Theorem 2.6. Suppose that u ∈ L1(0, b), i.e. U (0) < ∞. Then H is compact if and only if

x→b−lim A4(x; s) = 0 for every s > 0.

But if v1−p0 (or u) is not integrable over the whole interval (0, b), i.e., if V (b) = ∞ (or U (0) = ∞), then we need for the compactness of H that both limits of A2(x; s) (or A4(x; s) are zero: for x → 0+ and for x → b−. The following theorem is then an analogue of Theorem 2.1 for A2(x; s), and a similar assertion holds also for A4(x; s).

Theorem 2.7. Suppose that v1−p0 ∈ L/ 1(0, b), i.e. V (b) = ∞. Then the Hardy operator H is compact if and only if the function A2(x; s) has zero limits at x = 0 and x = b for any s > 0.

Proof. (i) Sufficiency. Due to Theorem 1.1, it is Jα .J2,α= sup

0<x<αA2(x; s).

In [2] it was shown that B1(x; α, β) .supx<t<bB2(t; α, β, s) (see estimates (2.4) and (2.5) in [2]). Putting here α = 1p, β = p10, we have

A1(x). sup

x<t<b

A2(t; s)

and this estimate implies Jβ = sup

β<x<b

A1(x, b, β). sup

β<x<b

A1(x). sup

β<x<b

A2(x; s).

If A2(x; s) → 0 for x → 0+ and for x → b, then Jα → 0 for α → 0+, Jβ → 0 for β → b, and hence H is compact.

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(ii) Necessity. Suppose that H is compact. Since A2(x; s) ≤ J2,α(s) for 0 < x < α, we have that limx→0+A2(x, s) = 0 due to Theorem 2.4. Hence, it remains to prove that

x→b−lim A2(x, s) = 0. (2.18)

Using the notation W (x) = Vq(p01+s)(x), we have for β < x < b

A2(x; s) = Z β

0 u(t)W (t)dt + Z x

β u(t)W (t)dt

!1/q

Vs(x)

Z β

0

u(t)W (t)dt

!1/q

+

Z x

β

u(t)W (t)dt

1/q

Vs(x)

=: I1+ I2. Since W (t) = Vq(

1 p0+s)

(t) = Vq(

1 p0+s)

(0, t) = [V (0, β) + V (β, t)]q(

1 p0+s)

, we have I2 =

Z x

β u(t) [V (0, β) + V (β, t)]q(

1 p0+s)

dt

1/q

Vs(0, x) .

Z x

β u(t) [V (0, β)]q(

1 p0+s)

dt

1/q

Vs(0, x) +

Z x

β

u(t) [V (β, t)]q(p01+s)dt

1/q

Vs(0, x)

=

Z x

β

u(t)dt

1/q

V (0, β)(p01+s)Vs(0, x) +

Z x

β

u(t)V (β, t)q(p01+s)dt

1/q

Vs(0, x)

=: I21+ I22.

Since V (0, x) = V (0, β) + V (β, x), it is V (0, x) ≥ V (0, β) as well as V (0, x) ≥ V (β, x). Consequently, it is Vs(0, x) ≤ Vs(0, β) and Vs(0, x) ≤ Vs(β, x). If we use these estimates in I21 and I22, we obtain

I21

Z x

β

u(t)dt

1/q

V (0, β)(p01+s)Vs(0, β)

= U1/q(β, x)V1/p0(0, β)

= A1(β; x, 0) ≤ A1(β; b, 0) = A1(β),

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I22

Z x

β u(t)V (β, t)q(

1 p0+s)

dt

1/q

Vs(β, x)

= A2(x; s; β, β) ≤ J2β(s).

Since H is compact, we have A1(β) → 0 and J2β(s) → 0 for β → b, and hence for a given small ε > 0 we can fix an β ∈ (0, b) such that

I2 ≤ C0A1(β) + J2β(s)< ε 2. Then we fix an x0 ∈ (β, b) such that

I1= Z β

0

u(t)Vq(p01+s)(t)dt

!1/q

Vs(x0) < ε 2

(notice that we assumed V (b) = ∞), and finally A2(x; s) < ε for x ∈ (x0, b), i.e.

we have (2.18).

Obviously, in a similar way we can prove:

Theorem 2.8. Suppose that u /∈ L1(0, b), i.e. U (0) = ∞. Then the Hardy operator H is compact if and only if the function A4(x; s) has zero limits at x = 0 and x = b for any s > 0.

3. Scales of Weight Characterization for the P´olya-Knopp Inequality In this section we will derive the corresponding scales of conditions for the weighted P´olya-Knopp inequality

Z 0

 exp

1 x

Z x

0 ln f (t)dt

q

u(x)dx

1/q

≤ C

Z

0 fp(x)v(x)dx

1/p

, (3.1) both for general measurable functions and for decreasing functions f ≥ 0. We consider the following known results. In [6] it was proved by B. Opic and P.

Gurka:

Theorem 3.1. Let 0 < p ≤ q < ∞. Then the inequality (3.1) holds for all f > 0 if and only if

DOG(r) = sup

x>0

Z x

w(t)tqrpdt

1/q

xr−1p < ∞, (3.2)

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where r > 1, and

w(t) =

 exp

1 t

Z t

0

ln 1 v(y)dy

q/p

u(t). (3.3)

In [8] L. E. Persson and V. D. Stepanov proved:

Theorem 3.2. Let 0 < p ≤ q < ∞. Then the inequality (3.1) holds for all f > 0 if and only if

DP S = sup

x>0

Z x

0

w(t)dt

1/q

x1/p< ∞ (3.4)

where w(t) is defined by (3.3).

Our main result in this section reads:

Theorem 3.3. Let 0 < p ≤ q < ∞, 0 < s < ∞, and define D1(s) = supx>0Rxw(t)tq(s+1/p)dt1/qxs,

D2(s) = supx>0R0xw(t)tq(s−p1)dt1/qxs, D3(s) = supx>0

 Rx

0

R

t w(y)y−qdyp

0(1qs)

dt



1 p0

(Rxw(t)tqdt)s,

D4(s) = supx>0

 R

x

R

t w(y)y−qdyp

0(1q+s)

dt

ps

(Rxw(t)tqdt)s,

(3.5)

with w(t) defined by (3.3). Then the P´olya-Knopp inequality (3.1) holds for all measurable functions f > 0 if and only if any of the quantities Di(s), i = 1, 2, 3, 4 is finite. Moreover, for the best constant C in (3.1) we have C ≈ Di(s), i = 1, 2, 3, 4.

Remark 3.1. The conditions (3.2) and (3.4) can be described in the follow- ing way

DOG= D1r−1p  with r > 1, DP S = D21p.

Hence Theorem 3.3 generalizes the corresponding results in [6] and [8].

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Proof of Theorem 3.3. In Theorem 1.1 we put a = 0, b = ∞, f (x) = w(x)xq with w(x) defined by (3.3), g(x) = 1, and choose α = 1q, β = p10. Then the assertion follows from the fact that

D1(s) = supx>0B2(x,1q,p10, s), D2(s) = supx>0B4(x,1q,p10, s), D3(s) = supx>0B3(x,1q,p10, s), D4(s) = supx>0B5(x,1q,p10, s),

are all equivalent to DOG = supx>0B1(x,1q,r−1p ) if we take r = sp + 1 in (3.2) (see Theorem 1.1) and the finiteness of (3.2) is necessary and sufficient for the inequality (3.1) to hold according to Theorem 3.1. Moreover, since for the least constant C in (3.1) we have C ≈ DOG it is clear that C ≈ Di(s), i = 1, 2, 3, 4 and the proof is complete.

In [2] also the Hardy inequality for decreasing functions f denoted f ↓ was characterized with scales of pairs of equivalent conditions by using Theorem 1.1 and the weight characterization given by E. Sawyer in [9] and by V. D. Stepanov in [10]. Our aim is now to characterize the weighted P´olya-Knopp inequality (3.1) for decreasing functions f , as far as we know this has not yet been done.

In [2] it was proved:

Theorem 3.4. Let 1 < p ≤ q < ∞, then the inequality

Z b 0

1 x

Z x

0 f (t)dtqu(x)dx1/q ≤ C Z b

0 fp(x)v(x)dx1/p (3.6) holds for all f ↓≥ 0 if and only if

A0(p, q, w, v, s) = sup

x>0

Z

x w(t)tq Z t

0 yp0Vp0(y)v(y)dyq(1−sp

0)/p0

dt1/q

× Z x

0 tp0Vp0(t)v(t)dts< ∞, (3.7) and

A1(p, q, w, v, s) = sup

x>0

Z x

w(t)Vqp(p0s+1)(t)dt

1/q

Vs(p01)(x) < ∞ (3.8)

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where

V (t) = Z t

0 v(x)dx. (3.9)

Moreover, if C is the best possible constant in (3.6) then C ≈ A0+ A1.

We have now the following result:

Theorem 3.5. Let 0 < p ≤ q < ∞ and v(x) be non-increasing. Then the inequality (3.1) holds for all f ↓ ≥ 0 if and only if

D := D(p, q, w, s)= sup

x>0

Z x

w(t)tq(s+1p)dt1/qxs< ∞, s > 0. (3.10) Moreover, if C is the best possible constant in (3.1), then C ≈ D.

Remark 3.2. The assumption that v(x) is non-increasing comes here natural as it was pointed out by Lorentz in [5] that kf kΛp(v) is a norm if and only if v(x) is non-increasing.

Proof. First we use the fact that as v(x) is non-increasing and if w(x) be defined as in (3.3). then (3.1) is equivalent to

Z 0

exp1 x

Z x

0

ln f (t)dtqw(x)dx

1

q ≤ C

Z 0

fp(x)dx

1

p (3.11)

and also

Z

0

exp1 x

Z x

0 ln f (t)dtq(s+

1 p)

w(x)dx

1

q ≤ C

Z

0 fps+1(x)dx

1

p. (3.12) Note that if s > 0 and 0 < p ≤ q < ∞ we have 1 < ps + 1 ≤ q(ps+1)p < ∞.

Furthermore, by applying Jensen’s inequality, we can obtain inequality (3.12) from the following inequality for all non-increasing functions f (x):

Z

0

1 x

x

Z

0

f (t)dtq(s+

1 p)

w(x)dx

1

q ≤ C

Z

0 fps+1(x)dx

1

p (3.13)

Now we take s = p10 and v(x) = 1 in (3.7) and s = p0(p101) and v(x) = 1 in (3.8) and find that

A0p, q, w, 1, 1 p0

= A1p, q, w, 1, 1 p0(p0− 1)

= Dp, q, w, 1 p0

.

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Moreover, if we replace p by sp + 1 and q by q(sp+1)p , take v(x) = 1 in inequality (3.6) and apply Theorem 3.4, we find that the inequality (3.13) (and thus the upper bound for (3.12)) holds if and only if



D(ps + 1,q(ps + 1)

p , w, ps ps + 1)



ps+1 p

= D(p, q, w, s) < ∞.

For the lower estimate we apply the test function

f (x) = t(s+1p)χ[0,t](x) + (xe)(s+1p)χ[t,∞](x) to (3.11) and the proof follows.

Now, by using again the equivalence theorem (Theorem 1.1) it is possible to generalize Theorem 3.5 as follows:

Theorem 3.6. Let 0 < p ≤ q < ∞, 0 < s < ∞, and let Di(s), i = 1, 2, 3, 4 be defined by (3.5). Then the inequality (3.1) holds for all f ↓ > 0 if and only if any of the quantities Di(s), i = 1, 2, 3, 4 is finite. Moreover, for the best constant C in (3.1) we have C ≈ Di(s), i = 1, 2, 3, 4.

Proof. In Theorem 1.1 we put a = 0, b = ∞, g(x) = 1 and f (x) = w(x)xq with w(x) defined by (3.3), and choose α = 1q, β = p10 as in the Proof of Theorem 3.3. Then the assertion follows from the fact that the functions in (3.5) are all equivalent to D = supx>0B1(x,1q,p10) defined in (3.10) (see Theorem 1.1), and the finiteness of (3.10) is necessary and sufficient for the inequality (3.1) to hold for all decreasing functions f according to Theorem 3.5. Moreover, since for the least constant C in (3.1) we have C ≈ D it is clear that C ≈ Di(s), i = 1, 2, 3, 4 and the proof is complete.

Acknowledgments

The research of the second author was partially supported by the grants A1019305 of the Academy of Science of the Czech Republic and 201/03/0671 of the Grant Agency of the Czech Republic.

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References

[1] R. K. Juberg, Measure of non-compactness and interpolation of compactness for a class of integral transformations, Duke Math. J., 41(1974), 511-525.

[2] A. Gogatishvili, A. Kufner, L. E. Persson and A. Wedestig, An equivalence theorem for some scales of integral conditions related to Hardy’s inequality with applications, Real Anal.

Exchange, 29(2004), 867-880.

[3] A. Kufner and L. E. Persson, Weighted Inequalities of Hardy Type, World Scientific Pub- lishing Co, Singapore, New Jersey, London, Hong Kong, 2003.

[4] A. Kufner, L. E. Persson and A. Wedestig, A study of some constants characterizing the weighted Hardy inequality, Orlicz Centenary Volume, Banach Center Publications 64(2004), 135-146.

[5] G. G. Lorentz, On the theory of spaces Λ, Pacific J. Math., 1(1951), 411-429.

[6] B. Opic and P. Gurka, Weighted inequalities for geometric means, Proc. Amer. Math. Soc., 3(1994), 771-779.

[7] B. Opic and A. Kufner, Hardy-type inequalities, Pitman Research Notes in Mathematics Series, Vol 211, Longman Scientific and Technical Harlow, 1990.

[8] L. E. Persson and V. D. Stepanov, Weighted integral inequalities with the geometric mean operator,J. Inequal. Appl., 7:5(2002), 727-746 (An abbreviated version can also be found in Russian Akad. Sci. Dokl. Math., 63(2001), 201-202).

[9] E. T. Sawyer, Boundedness of classical operators on classical Lorentz spaces, Studia Math., 96(1990), 145-158.

[10] V. D. Stepanov, The weighted Hardy’s inequality for nonincreasing functions, Trans. Amer.

Math. Soc., 338:1(1993), 173-186.

Matematical Institute Academy of Sciences of the Czech Republic, Zitna 25, 115 67 Praha 1, CZECH REPUBLIC.

E-mail: gogatish@math.cas.cz E-mail: kufner@math.cas.cz

Department of Mathematics, Lule˚a University of Technology, SE-971 87 Lule˚a, SWEDEN.

E-mail: larserik@sm.luth.se E-mail: annaw@sm.luth.se

References

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