2014-02-19 Lösa ut storheterna inom parantes.doc
Algebra med fysik!
Lösa ut variablerna inom parantes
1. a) (x
)
2
⋅ x
+
5
=
3
b) (x)6
3
=
x
c) (x)3
=
5
x
d) (x)5
6
0
2=
+
− x
x
2. a) (v)s
=
v
⋅
t
b) (F)A
F
p =
c) (V)
V
m
=
ρ
d) (Δv)t
v
a
Δ
Δ
=
e) (t)W
=
P
⋅
t
f) (s)s
W
F =
3. a) (h)W
=
m
⋅
g
⋅
h
b) (A)g
A
p
m
=
⋅
c) (m)Q
=
c
⋅
m
⋅
Δ
T
d) (ρ)V
F
g
L⋅
=
ρ
e) (π)π
ω
⋅
=
2
f
f (r)T
r
v
=
2
⋅
π
⋅
4. a) (r)A
=
4
⋅
π
⋅
r
2 b) (I)P
=
I
2⋅
R
c) (v)2
2v
m
W
=
⋅
d) (v)r
v
m
F
2⋅
=
e) (r) 1 2 2r
q
q
k
F
=
⋅
⋅
f) (t) 22
t
s
g
=
⋅
5. a) (U1) 2 2 1 1R
U
R
U
=
b) (R2) 2 2 1 1R
U
R
U
=
c) (s)m
⋅
g
⋅
h
=
F
⋅
s
d) (m)U
⋅
I
=
m
⋅
g
⋅
v
e) (r)r
v
m
r
q
k
2 2 2⋅
=
⋅
f) (v)2
2v
m
h
g
m
⋅
⋅
=
⋅
2014-02-19 Lösa ut storheterna inom parantes.doc